1 only........cause a prime number is always a odd.....so if we add q 3 thats even....but p is odd
p=5 and q=2 is one obvious solution.
Now suppose both p, q>3.
p and q can only be of the forms 6k+1 or 6k+5.
Since p-q=3, both must be of the same forms.
But then difference will be divisible by 6.
Therefore, p-q cannot be equal to 3.
Thus, p=5, q=2 is the only possible solution.
Abhishek did B. Tech. in Computer Science & Engineering from IIT Kanpur in 2005. Thereafter he joined Indian Revenue Service (IRS) in 2006. He has deep interests in science. He authored the book “Mathematics for Learning Physics”, published by Arihant Publications. This book is designed to be used as the first book after class X and addresses difficulty faced by fresh pass-outs from class X in understanding Physics of class XI on account of non-familiarity with mathematical tools(calculus etc)
Abhishek Kumar
Mar 24th, 2019